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11/13/2020
Unifiedcamp
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maths
Ring
Expand (1+3x)^⅓ up to the term in x⁴
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Emperor
11/13/2020
I) Tn= (3+5n)/2
ii) Sn= ((n/2)(11+5n)/2)
Emperor
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Answers ( 1 )
I) Tn= (3+5n)/2
ii) Sn= ((n/2)(11+5n)/2)
Emperor
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