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  1. User
    6/15/2020

    By: Rid007

    3x³+kx²_4x+6 divided by x_4 gives remainder of 22

    Solution:

    Let f(x) =3x³ + kx² _ 4x +6

    X_4=0

    X=4

    F(4)= 192 + 16k _16 + 6=22

    = 182 + 16k = 22

    182_ 22= _16k

    160 = _16k.     Divide both sides by _16

    K= _10.

     

    Good Answer